# How do you find the derivative of #1/3 (x^2-3x-5) * (2x-3)#?

##### 1 Answer

May 7, 2018

#### Explanation:

#"differentiate using the "color(blue)"power rule"#

#•color(white)(x)d/dx(ax^n)=nax^(n-1)#

#"expand factors and distribute"#

#=1/3(2x^3-9x^2-x+15)#

#=2/3x^3-3x^2-1/3x+5#

#d/(dx)(2/3x^3-3x^2-1/3x+5)#

#=2x^2-6x-1/3#