Question

How do you find the derivative of `1/(x^2) - 1/x`?

Answer 1

`-2/x^3+1/x^2`

Explanation:

This can be done with the quotient rule, but the easiest thing to do is to first rewrite:

`1/x^2-1/x = x^(-2)-x^(-1)`

`d/dx(1/x^2-1/x) = d/dx(x^(-2)-x^(-1)) = -2x^(-3) -(-1)x^(-2)`
`=-2/x^3+1/x^2`