How do you find the derivative of #2x-1#?

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Answer 1 · 2018-03-02T14:00:18

#2#

Subtraction Derivative rule:

#d/(dx)a-b = d/(dx)a - d/(dx)b#

Here, we can substitute:

#d/dx(2x-1)#

#=[d/(dx)2x]-[d/dx-1]#

#(2x)'=2#
#(-1)'=0# (the derivative of any constant #=0#)

So:

#[2]-[0]#

#=2-0#

#=2#

Thus, solved.