How do you find the derivative of #[(2x^3) - (4x^2) + 3] / x^2 #?
1 Answer
Mar 16, 2016
Explanation:
You could differentiate this function using the ' Quotient rule ' but probably 'easier' to divide each term by
# x^2 #
#(2x^3 - 4x^2 + 3)/x^2 = ((2x^3)/x^2 - (4x^2)/x^2 +3/x^2)# which simplifies to :
# 2x - 4 + 3x^-2 #
#rArr d/dx(2x-4+3x^-2) = 2 - 6x^-3 = 2 - 6/x^3 #
