# How do you find the derivative of 8/x^2?

One law of exponentials states that ${a}^{-} n = \frac{1}{a} ^ n$
Thus, we can rewrite this again as $8 {x}^{-} 2$
$\frac{\mathrm{dy}}{\mathrm{dx}} = 8 \left(- 2\right) {x}^{-} 3 = - 16 {x}^{-} 3$
If you prefer, $- \frac{16}{x} ^ 3$