# How do you find the derivative of #arcsin(x^2)#?

##### 1 Answer

Dec 14, 2017

#### Explanation:

Letting

Then differentiating both sides with respect to

#cosy(dy/dx) = 2x#

#dy/dx = (2x)/cosy#

We know that

#dy/dx = (2x)/sqrt(1 - sin^2y)#

Recall that

#dy/dx = (2x)/sqrt(1 - x^4)#

Hopefully this helps!