How do you find the derivative of #f(u)=sqrtu+2#?

1 Answer
Jan 11, 2017

#f'(u)=1/(2sqrtu)#

Explanation:

differentiate using the #color(blue)"power rule"#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx(ax^n)=nax^(n-1))color(white)(2/2)|)))#

express #sqrtu" in the form " u^(1/2)#

#f(u)=u^(1/2)+2#

#rArrf'(u)=1/2u^(-1/2)+0=1/(2u^(1/2))=1/(2sqrtu)#