How do you find the derivative of #f(x)=1-2x^2#?

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Answer 1 · 2017-06-16T22:06:24

#d/dx=-4x#

We find the derivative using the power rule:

#d/dxx^n=nx^(n-1)#

Simply to put it into words bring down the exponent and multiply it by the n (n in our case is equal to #2#) and subtract 1 from the exponent.

The derivative of a constant is always zero:

#d/dxc=0#

Knowing this we can now move forward:

#f'(x)=d/dx1-d/dx2x^2#

#f'(x)=0-2(2)x^(2-1)#

#f'(x)=-4x#