Question

How do you find the derivative of `f(x)=1/2x^4-2x^3+1/3x-4`?

Answer 1

The answer is `=2x^3-6x^2+1/3`

Explanation:

Here we are calculating the derivatives of powera of `x`

`(x^n)'=nx^(n-1)`

`f(x)=x^4/2-2x^3+x/3-4`

Then,

`f'(x)=(4x^3)/2-2*3x^2+1/3`

`=2x^3-6x^2+1/3`