Question

How do you find the derivative of `f(x)=(1/x^2)`?

Answer 1

`f'(x)=-2x^-3.`

Explanation:

`y=x^n rArr dy/dx=nx^(n-1).`

Given that `f(x)=1/x^2=x^-2.`

Hence, `f'(x)=-2x^(-2-1), = -2x^-3.`