# How do you find the derivative of  f(x)=(1/x^2)?

$f ' \left(x\right) = - 2 {x}^{-} 3.$
$y = {x}^{n} \Rightarrow \frac{\mathrm{dy}}{\mathrm{dx}} = n {x}^{n - 1} .$
Given that $f \left(x\right) = \frac{1}{x} ^ 2 = {x}^{-} 2.$
Hence, $f ' \left(x\right) = - 2 {x}^{- 2 - 1} , = - 2 {x}^{-} 3.$