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How do you find the derivative of #f (x) = 3x^5 + 4x# using the limit definition?

1 Answer

Mar 29, 2018

#f'(x)=15x^4+4#

Explanation:

The basic rule is that #x^n# becomes #nx^(n-1)#

So #5*3x^(5-1)+1*4x^(1-1)#

Which is
#f'(x)=15x^4+4#

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