Question

How do you find the derivative of `f(x) = 3xsin(2x)^2`?

Answer 1

`(df(x))/(dx)=3sin(2x)^2+24x^2cos(2x)^2`

Explanation:

To find the derivative of `f(x)=3xsin(2x)^2`, we use poduct formula and chain rule.

`(df(x))/(dx)=1xx3sin(2x)^2+3x xxcos(2x)^2xx8x`

= `3sin(2x)^2+24x^2cos(2x)^2`