How do you find the derivative of $f(x)=e^(8x)+cos(x)sin(x)$ ?

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Answer 1 · 2016-05-28T08:44:17

$d /(d x) f(x)=8*e^(7x)*l n e+1-2sin^2 x$

$f(x)=e^(8x)+cos(x)sin(x)$

$d /(d x) f(x)=8*e^(7x)*l n e-sin x*sin x +cos x *cos x$

$d /(d x) f(x)=8*e^(7x)*l n e-sin^2 x+cos^2 x$

$cos^2 x=1-sin^2 x$

$d /(d x) f(x)=8*e^(7x)*l n e-sin^2 x+(1-sin^2 x)$

$d /(d x) f(x)=8*e^(7x)*l n e-sin^2 x+1-sin^2 x$

$d /(d x) f(x)=8*e^(7x)*l n e+1-2sin^2 x$

How do you find the derivative of f(x)=e^(8x)+cos(x)sin(x) f(x)=e^(8x)+cos(x)sin(x)?