Question

How do you find the derivative of `f(x) = (ln x)^2`?

Answer 1

I found: `f'(x)=(2ln(x))/x`

Explanation:

You can use the Chain Rule deriving the `()^2` first and then the `ln`:
`f'(x)=2(ln(x))^1*1/x=(2ln(x))/x`