How do you find the derivative of #f(x)=root3(x)+root5(x)#?
1 Answer
Mar 2, 2017
You convert to fractional exponents.
#d/(dx)[x^"1/3" + x^"1/5"]#
#= 1/3x^-"2/3" + 1/5x^-"4/5"#
#= 1/(3x^"2/3") + 1/(5x^"4/5")#
#= color(blue)(1/(3root(3)(x^2)) + 1/(5root(5)(x^4)))#
