How do you find the derivative of #f(x)=sqrt(x+1)#?
1 Answer
Mar 3, 2018
Explanation:
#"differentiate using the "color(blue)"chain rule"#
#"given "f(x)=g(h(x))" then"#
#f'(x)=g'(h(x))xxh'(x)larrcolor(blue)"chain rule"#
#f(x)=sqrt(x+1)=(x+1)^(1/2)#
#rArrf'(x)=1/2(x+1)^(-1/2)xxd/dx(x+1)#
#color(white)(rArrf'(x))=1/(2(x+1)^(1/2))=1/(2sqrt(x+1))#
