# How do you find the derivative of f(x) = (x^2-4)/(x-2) ?

$f ' \left(x\right) = 1$ for $x \ne 2$.
${x}^{2} - 4 = \left(x + 2\right) \left(x - 2\right)$, so we can reduce quotient for $x \ne 2$.
$f \left(x\right) = x + 2$ for $x \ne 2$,
so $f ' \left(x\right) = 1$ for $x \ne 2$.