How do you find the derivative of #f(x)=x^2+4x+8#?
1 Answer
Dec 9, 2016
#f^'(x)=2x+4#
Explanation:
Given -
#f(x)=x^2+4x+8#
#f^'(x)=(1 xx 2)x^(2-1)+(4 xx 1)x^(1-1)+0#
#f^'(x)=2x+4#
