Question

How do you find the derivative of `f(x)=x^3-3x`?

Answer 1

`3x^2 - 3`

Explanation:

using

If `y = ax^n then dy/dx = nax^(n-1)`

here `f(x) = x^3 - 3x`

hence f'(x) = `3x^(3-1) - 3x^(1-1) = 3x^2 -3x^0 = 3x^2 - 3`

(since `x^0 = 1)`