Question

How do you find the derivative of `f(x)= x(3-9)^3`?

Answer 1

`f'(x) = -216`

Explanation:

`f(x) = x(3-9)^3`
`(3-9)^3 = (-6)^3 = -216` is a constant

So `f(x) = -216x`

We then use the power rule `d/dxx^n=nx^(n-1)`

Giving `f'(x) = -216`

Answer 2

Perhaps you meant to write `f(x)=x(3x-9)^3`?