Question

How do you find the derivative of `g(t)=(10log_4t)/t`?

Answer 1

`(dg)/(dt)=10/ln4*(1-lnt)/t^2`

Explanation:

What is required is to convert base `4` of log to base `e` and then use quotient formula

`g(t)=(10log_4t)/t`

`=(10lnt)/(ln4t)`

Hence `(dg)/(dt)=10/ln4xx(txx1/t-lnt)/t^2`

`=10/ln4*(1-lnt)/t^2`