How do you find the derivative of #g(x)=x^2+4x^3#?
1 Answer
Aug 1, 2017
Explanation:
#"differentiate each term using the "color(blue)"power rule"#
#•color(white)(x)d/dx(ax^n)=nax^(n-1)#
#g(x)=x^2+4x^3#
#rArrg'(x)=(2xx1)x^((2-1))+(3xx4)x^((3-1))#
#color(white)(rArrg'(x))=2x+12x^2#
