# How do you find the derivative of h(x) = (2x^2-3x+1)/x?

You can write the function $h \left(x\right)$ as follows
$h \left(x\right) = 2 x - 3 + \frac{1}{x}$
$d \frac{h \left(x\right)}{\mathrm{dx}} = 2 - \frac{1}{x} ^ 2$