Question

How do you find the derivative of `ln(10/x)`?

Answer 1

`d/dxln(10/x) = -1/x`

Explanation:

Simply the expression using the rule of logs and use `d/dx(lnx)=1/x`

So, `d/dxln(10/x) = d/dx{ln10-lnx}`

`= d/dxln10-d/dxlnx`
`= 0-1/x`
`= -1/x`