Question

How do you find the derivative of `ln((4x^2)+9)` and what are the intervals for which the results are valid?

Answer 1

The answer is: `y'=(8x)/(4x^2+9)`

and the interval is `(-oo,+oo)`, because this function has `R` as domain.

We have to use the chain rule, so:

`y'=1/(4x^2+9)*8x`.