Question

How do you find the derivative of `ln(e^(4x)+3x)`?

Answer 1

`(4 e^(4x)+3)/( e^(4x)+3x)`

Explanation:

y = log u, where u = `e^(4x)+3`

`y'=(dy)/(du) u'`

`= 1/u(4e^(4x)+3)`

`=(4 e^(4x)+3)/( e^(4x)+3x)`