Question

How do you find the derivative of `ln(sec^2 * x)`?

Answer 1

`d/dxln(sec^2x)=2tanx`

Explanation:

Using the logarithm property for exponents, we may rewrite as

`ln(sec^2x)=2ln(secx)`

Differentiating this will now only require one application of the Chain Rule:
`d/dx2ln(secx)=2/secx*d/dxsecx`

`=(2cancelsecxtanx)/(cancelsecx)=2tanx`