How do you find the derivative of # ln -x#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Calculators 1 Answer Eddie Jun 28, 2016 #d/dx ln (-x) = 1/x# Explanation: as a rule #d/dx ln (f(x)) = 1/f(x) f'(x)# here #f(x) = - x # and #f'(x) = -1# so we have #d/dx ln (-x) = 1/(-x)*-1 = 1/x# Answer link Related questions How do you use a calculator to find the derivative of #f(x)=e^(x^2)# ? How do you use a calculator to find the derivative of #f(x)=e^(1-3x)# ? How do you use a calculator to find the derivative of #f(x)=e^sqrt(x)# ? What is the derivative of #e^(-x)#? What is the derivative of #ln(2x)#? How do you differentiate #(lnx)^(x)#? How do you differentiate #x^lnx#? How do you differentiate #f(x) = e^xlnx#? How do you differentiate #e^(lnx) #? How do you differentiate #y = lnx^2#? See all questions in Differentiating Exponential Functions with Calculators Impact of this question 1729 views around the world You can reuse this answer Creative Commons License