How do you find the derivative of #ln(x^3+3x)^3#?

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Answer 1 · 2015-04-07T19:41:54

I would use the Chain Rule after rearranging the #ln# as:
#ln(x^3+3x)^3=3ln(x^3+3x)#
So deriving you get:
#3*1/(x^3+3x)*(3x^2+3)=9(x^2+1)/(x(x^2+3))#