Question

How do you find the derivative of `lnx / x`?

Answer 1

`(1-lnx)/x^2`

Explanation:

`f(x) = lnx/x`

`f'(x) = (x*1/x - lnx*1)/x^2` (Quotient rule and standard differential)

`= (1-lnx)/x^2`