How do you find the derivative of #r= 2theta sqrt(sec theta)# using the chain rule?

1 Answer
Sep 16, 2017

Answer:

#(dr)/(d theta)=sqrtsectheta (2+thetatantheta)#

Explanation:

#r=2thetasqrtsectheta#
Differentiating both sides with respect to #theta# we get
#(dr)/(d theta)=2sqrtsectheta + 2theta×1/(2sqrtsectheta)secthetatantheta#
#=2sqrtsectheta+thetasqrtsecthetatantheta#
#=sqrtsectheta (2+thetatantheta)#