# How do you find the derivative of #sqrt(3x+1)#?

##### 1 Answer

Jan 11, 2017

First off, recall that the derivative of

Now, in your expression,

#(df)/(dx) = (df)/(du)(du)/(dx)# for

#f(u) = sqrt(u(x)) = sqrt(3x + 1)# .

So, taking the derivative, we have:

#color(blue)(d/(dx)[sqrt(3x + 1)]) = 1/(2sqrt(u(x))) * (du)/(dx)#

#= 1/(2sqrt(3x + 1)) * d/(dx)[3x + 1]#

#= color(blue)(3/(2sqrt(3x + 1)))#