# How do you find the derivative of sqrt(4+x^2)?

$\frac{d}{\mathrm{dx}} \left({\left(4 + {x}^{2}\right)}^{\frac{1}{2}}\right) = \setminus \frac{1}{2} {\left(4 + {x}^{2}\right)}^{- \frac{1}{2}} \setminus \cdot 2 x = \frac{x}{\sqrt{4 + {x}^{2}}}$