# How do you find the derivative of sqrt(8x+1)?

Feb 4, 2016

here is how you do it,

#### Explanation:

for this, we have to use chain rule.

$\frac{d}{\mathrm{dx}} \left(\sqrt{8 x + 1}\right)$

$= \frac{1}{2 \sqrt{8 x + 1}} \frac{d}{\mathrm{dx}} \left(8 x + 1\right)$

$= \frac{8}{2 \sqrt{8 x + 1}}$

$= \frac{4}{\sqrt{8 x + 1}}$