How do you find the derivative of #sqrt(9-x)#?
1 Answer
Mar 10, 2016
Explanation:
differentiate using the
#color(blue)" chain rule " #
#d/dx[f(g(x))] = f'(g(x)) . g'(x)# now
#sqrt(9-x) = (9-x)^(1/2) #
#rArr d/dx(9-x)^(1/2) = 1/2(9-x)^(-1/2) .d/dx(9-x)#
# = -1/(2sqrt(9-x))#
