# How do you find the derivative of the function f(x)=9x^2ln(8x)?

The answer is: $y ' = 9 x \left(2 \ln 8 x + 1\right)$.
$y ' = 9 \left(2 x \cdot \ln 8 x + {x}^{2} \cdot \frac{1}{8 x} \cdot 8\right) = 9 \left(2 x \cdot \ln 8 x + x\right) =$
$= 9 x \left(2 \ln 8 x + 1\right)$.