How do you find the derivative of #(x-1)/(x+1)#?
1 Answer
Explanation:
Use the quotient rule, which states that
#d/dx(f(x)/g(x))=(g(x)f'(x)-f(x)g'(x))/g(x)^2#
Here, we see that
#f(x)=x-1#
#g(x)=x+1#
So both their derivatives equal
#f'(x)=1#
#g'(x)=1#
Thus, using the first equation,
#d/dx((x-1)/(x+1))=((x+1)(1)-(x-1)(1))/(x+1)^2#
#color(white)(XXXX.lXX)=2/(x+1)^2#
