How do you find the derivative of # x / 2 #?
2 Answers
Jun 20, 2016
Explanation:
Expressing
#x/2=1/2x# now differentiate using the
#color(blue)"power rule"#
#d/dx(ax^n)=nax^(n-1)#
#rArrd/dx(1/2x^1)=(1xx1/2)x^(1-1)=1/2x^0=1/2xx1=1/2#
Jun 25, 2016
Explanation:
Let
#f'(x)=lim_(hrarr0)(f(x+h)-f(x))/h=lim_(hrarr0)((x+h)/2-x/2)/h#
Multiplying the fraction by
#f'(x)=lim_(hrarr0)((x+h)-x)/(2h)=lim_(hrarr0)h/(2h)=lim_(hrarr0)1/2=1/2#