How do you find the derivative of # x^2e^x-xe^x#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Base e 1 Answer mmm Apr 25, 2018 # (x^2)'e^x+x^2(e^x)'-((x)'(e^x)+x(e^x)') = 2xe^x+x^2e^x-(e^x+xe^x) = (x^2+x-1)e^x# Explanation: Use product rule. Answer link Related questions What is the derivative of #y=3x^2e^(5x)# ? What is the derivative of #y=e^(3-2x)# ? What is the derivative of #f(theta)=e^(sin2theta)# ? What is the derivative of #f(x)=(e^(1/x))/x^2# ? What is the derivative of #f(x)=e^(pix)*cos(6x)# ? What is the derivative of #f(x)=x^4*e^sqrt(x)# ? What is the derivative of #f(x)=e^(-6x)+e# ? How do you find the derivative of #y=e^x#? How do you find the derivative of #y=e^(1/x)#? How do you find the derivative of #y=e^(2x)#? See all questions in Differentiating Exponential Functions with Base e Impact of this question 5825 views around the world You can reuse this answer Creative Commons License