# How do you find the derivative of x^2y?

$d \frac{\left(u . v\right)}{\mathrm{dx}} = u . \frac{\mathrm{dv}}{\mathrm{dx}} + v . \frac{\mathrm{du}}{\mathrm{dx}}$
$\left({x}^{2} y\right) ' = {x}^{2.} \frac{\mathrm{dy}}{\mathrm{dx}} + y 2 x$
$\left({x}^{2} y\right) ' = {x}^{2} y ' + 2 y x$