How do you find the derivative of #(x-3) /( 2x+1)#?

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Answer 1 · 2016-06-24T19:54:40

#= ( 7 )/( 2x+1)^2#

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#((x-3) /( 2x+1))'#

#= ((x-3)'( 2x+1) - (x-3)( 2x+1)' )/( 2x+1)^2#

#= ((1)( 2x+1) - (x-3)( 2) )/( 2x+1)^2#

#= ( 2x+1 - 2x+6 )/( 2x+1)^2#

#= ( 7 )/( 2x+1)^2#