# How do you find the derivative of x/(x+1)?

$\frac{1}{x + 1} ^ 2$
${\left(\frac{x}{x + 1}\right)}^{p} r i m e = \frac{x ' \left(x + 1\right) - x \left(x + 1\right) '}{x + 1} ^ 2$
$= \frac{x + 1 - x}{x + 1} ^ 2$
$= \frac{1}{x + 1} ^ 2$