Question

How do you find the derivative of `x(y^2)-2(x^3)y=x+y`?

Answer 1

`y'=(1-y^2+6x^2y)/(2xy-2x^3-1)`

Explanation:

`2xyy'+y^2-2x^3y'-6x^2y=1+y'`

`2xyy'-2x^3y'-y'=1-y^2+6x^2y`

`y'(2xy-2x^3-1)=1-y^2+6x^2y`

`y'=(1-y^2+6x^2y)/(2xy-2x^3-1)`