# How do you find the derivative of y=1/(1+1/t)?

I would begin by writing $y = \frac{t}{t + 1}$ then use the quotient rule.
$\frac{\mathrm{dy}}{\mathrm{dt}} = \frac{\left(1\right) \left(t + 1\right) - \left(t\right) \left(1\right)}{t + 1} ^ 2 = \frac{1}{t + 1} ^ 2$