How do you find the derivative of #y=(1+e^x)^(-2)#?
1 Answer
Jul 4, 2017
Explanation:
#"differentiate using the "color(blue)"chain rule"#
#"given " y=f(g(x))" then"#
#dy/dx=f'(g(x))xxg'(x)larr" chain rule"#
#y=(1+e^x)^-2#
#rArrdy/dx=-2(1+e^x)^(-3)xxd/dx(1+e^x)#
#color(white)(rArrdy/dx)=-2e^x(1+e^x)^(-3)#
