How do you find the derivative of #y=1/x^2#?
1 Answer
Jan 14, 2016
#dy /dx = -2/x^3 #
Explanation:
The derivative of
# y = ax^n # is
#dy/dx = nax^(n-1) # By rewriting
# y = 1/x^2 # as#y = x^(-2) # then it is in the form
# ax^n #
