# How do you find the derivative of y=10x^-2 + 3x^-4 - 6x?

May 27, 2016

$\frac{d y}{d x} = - 20 \cdot {x}^{- 3} - 12 \cdot {x}^{- 5} - 6$

#### Explanation:

$y = 10 \cdot {x}^{- 2} + 3 {x}^{- 4} - 6 x$

$y = a {x}^{k} + b {x}^{m} + c$

$\frac{d y}{d x} = a \cdot k \cdot {x}^{k - 1} + b \cdot m \cdot {x}^{m - 1} + 0$

$\frac{d y}{d x} = - 20 \cdot {x}^{- 3} - 12 \cdot {x}^{- 5} - 6$