How do you find the derivative of #y=2^(-3/x)#?
1 Answer
Aug 13, 2017
#dy/dx = 2^(-3/x)(3/x^2)ln2#
Explanation:
Use logarithmic differentiation.
#lny = ln(2^(-3/x))#
#lny = -3/xln(2)#
#lny = -3x^-1(ln2)#
#lny = -3ln2x^-1#
#1/y(dy/dx)= 3ln2x^(-2)#
#dy/dx = 2^(-3/x)(3/x^2)ln2#
Hopefully this helps!
