How do you find the derivative of y=(3x-4)(5x+1)?

Apr 10, 2016

$\frac{d}{\mathrm{dx}} \left\{\left(3 x - 4\right) \left(5 x + 1\right)\right\} = 30 x - 17$

Explanation:

$\frac{d}{\mathrm{dx}} \left\{\left(3 x - 4\right) \left(5 x + 1\right)\right\}$

= $\left(3 x - 4\right) \frac{d}{\mathrm{dx}} \left(5 x + 1\right) + \left(5 x + 1\right) \frac{d}{\mathrm{dx}} \left(3 x - 4\right)$

= $\left(3 x - 4\right) \cdot 5 + \left(5 x + 1\right) \cdot 3$

= $15 x - 20 + 15 x + 3$

= $30 x - 17$