How do you find the derivative of #y=(3x-4)(5x+1)#? Calculus Basic Differentiation Rules Product Rule 1 Answer Shwetank Mauria Apr 10, 2016 #d/dx{(3x-4)(5x+1)}=30x-17# Explanation: #d/dx{(3x-4)(5x+1)}# = #(3x-4)d/dx(5x+1)+(5x+1)d/dx(3x-4)# = #(3x-4)*5+(5x+1)*3# = #15x-20+15x+3# = #30x-17# Answer link Related questions What is the Product Rule for derivatives? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x - 3)(2 - 3x)(5 - x)# ? How do you use the product rule to find the derivative of #y=x^2*sin(x)# ? How do you use the product rule to differentiate #y=cos(x)*sin(x)# ? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x^4 +x)*e^x*tan(x)# ? How do you use the product rule to find the derivative of #y=(x^3+2x)*e^x# ? How do you use the product rule to find the derivative of #y=sqrt(x)*cos(x)# ? How do you use the product rule to find the derivative of #y=(1/x^2-3/x^4)*(x+5x^3)# ? How do you use the product rule to find the derivative of #y=sqrt(x)*e^x# ? How do you use the product rule to find the derivative of #y=x*ln(x)# ? See all questions in Product Rule Impact of this question 2397 views around the world You can reuse this answer Creative Commons License