How do you find the derivative of #y=3x^4 - sqrt(x)/9 + 4/x^3 + 6xsqrt(x)#?

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Answer 1 · 2015-09-15T02:00:16

Refer to explanation

We rewrite it as follows

#y=3x^4-1/9*x^(1/2)+4*x^-3+6x^(3/2)#

hence the derivative is

#y'=12x^3-1/9*(1/2)x^(-1/2)-12x^-4+6*3/2x^(1/2)=> y'=12x^3-1/18x^(-1/2)-12x^-4-9x^(1/2)#

Answer 2 · 2015-09-15T02:19:10

Refer Explanation section

As far as possible I simplified the process

Follow the steps